Question

A train clears a platform of 200 meters long in 10 seconds and passes a telegraph post in 5 seconds. The length of the train is :

• A. 100 meters
• B. 200 meters
• C. 300 meters
• D. 400 meters

Answer 1

Answer:

B. 200 meters

Let speed of train be 'x' m/sec and length of train be 'y' m, then x = (200 + y)/10 x = y/5 y/5 = (200 + y)/10 ⇒ 2y = 200 + y ⇒ 2y – y = 200 ⇒ y = 200