Question

D, L, P, Q, and E are sitting in a circular table facing the centre (but not necessarily in the same order). P is an immediate neighbour of both Q and E. L is sitting to the immediate left of E. Q is is an immediate neighbour of both P and D. Who are the immediate neighbours of D?

• A. P and E
• B. E and L
• C. Q and L
• D. Q and P

Answer 1

Answer:

C. Q and L

Let’s build it step by step (all facing the centre).

Key idea:

• Facing centre ⇒ left is clockwise, right is anticlockwise.

  Use the strongest condition

P is an immediate neighbour of both Q and E

So arrangement must be:

Q – P – E (in some order around P)

So P is in the middle of Q and E.

We temporarily fix:
Q – P – E

Use “Q is also neighbour of D”

So Q must sit next to D.

So around Q, we now have:

• D on one side

• P on the other side

So we get:
D – Q – P – E (or reverse direction)

Use “L is immediate left of E”

Since everyone faces centre:

• Left = clockwise

So L must be immediately clockwise from E.

So we place:
E → L

Now chain becomes:
D – Q – P – E – L

Place remaining person

Only one seat left, which fits correctly to complete the circle.

So full circle:
D – Q – P – E – L

Find neighbours of D

From arrangement:

D sits next to:

• L

• Q

  Final Answer: L and Q