Question

Find the value of

$[(44 \div 4) \times [\frac{48}{8}+\frac{21}{5}\times(7-2)]]$

• A. 296
• B. 299
• C. 313
• D. 297

Answer 1

Answer:

D. 297

$\Big[ (44 \div 4) \times \Big( \frac{48}{8} + \frac{21}{5} \times (7-2) \Big) \Big]$

1. (44 \div 4 = 11)

2. (48 \div 8 = 6)

3. (7 - 2 = 5)

4. (\frac{21}{5} \times 5 = 21)

Now the inner bracket becomes:

$\frac{48}{8} + \frac{21}{5} \times (7-2) = 6 + 21 = 27$

Step 2: Multiply by 11
$11 \times 27 = 297$