Question

$\frac {7^2 \times 9^3}{27 \times 343} = ?$

• A. $\frac {27}{7}$
• B. $\frac {27}{21}$
• C. $\frac {7}{27}$
• D. $\frac {21}{27}$

Answer 1

Answer:

$\frac {27}{7}$

$\frac {7^2 \times 9^3}{27 \times 343}$

$= \frac {7^2 \times 9^3}{3^3 \times 7^3}$

$= \frac {7^2 \times (3^{2)^3}}{3^3 \times 7^3}$

$= \frac {7^2 \times 3^6}{3^3 \times 7^3}$

$= \frac {3^3}{7}$

$= 27/7$