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You are given three bulbs of 25, 40 and 60 watts. Which of them has lowest resistance ?

A25 watts

B40 watts

C60 watts

DNone of the above

Answer:

C. 60 watts

Read Explanation:

  • The power consumed by an electrical appliance like a bulb is related to the voltage across it and the current flowing through it. The fundamental formula is P = V * I, where P is power, V is voltage, and I is current.

  • Using Ohm's Law (V = I * R), we can derive other useful relationships.

  • When voltage (V) is constant (as is typically the case for household bulbs connected to the same mains supply), the power dissipated by a resistor is given by: P = V^2 / R.

  • Rearranging this formula to find resistance, we get: R = V^2 / P.

  • We are given three bulbs with power ratings of 25 W, 40 W, and 60 W.

  • Since all bulbs are assumed to be connected to the same voltage source (e.g., household electricity), the voltage (V) is constant for all of them.

  • From the formula R = V^2 / P, we can see that resistance (R) is inversely proportional to power (P) when voltage is constant. This means that a higher power rating will correspond to a lower resistance.


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