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ഒരു ട്രെയിൻ ഒരു പോസ്റ്റിനെ മറികടക്കുന്നതിന് 10 സെക്കൻഡ് 200m നീളമുള്ള പ്ലാറ്റ്ഫോം മറികടക്കുന്നതിന് 20 സെക്കൻഡ് എടുക്കും എങ്കിൽ ട്രെയിനിന്റെ നീളം എത്ര ?

A200 m

B400 m

C600 m

D800 m

Answer:

A. 200 m

Read Explanation:

ട്രെയിനിന്റെ നീളം x ആയാൽ ട്രെയിനിന്റെ വേഗത എപ്പോഴും തുല്യമായിരിക്കും x / 10 = (x+200)/20 20x = 10(x+200) 20x = 10x + 2000 10x = 2000 x = 200


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