Question:
In a group of cows and hens, the number of legs are 14 more than twice the number of heads. The number of cow is:
A5
B7
C10
D12
Answer:
B. 7
Explanation:
Let the number of cows be x and the number of hens be y Total Number of Heads = 1 for cow + 1 for hen = (1x+1y )Heads Total Number of Legs = Cows has 4 + Hen has 2 = (4x+2y)Legs Then 4x+2y=2(1x+1y)+14 4x+2y=2x+2y+14 => 2x=14 x=7