The cost of 8A is equal to the cost of 50B. The cost of 19C is 456. The cost of B is twice the cost of 2C. What is the total cost of 3A and 4B together?A2184B2022C2080D1996Answer: A. 2184Read Explanation:CP of 8A= CP of 50B => A/B=50/8 A : B= 50:8=>25:4 Let CP of A is 25x and CP of B is 4x19C = 456 => C=24 CP of B=2 times the CP of 2C=3×2×243\times{2}\times{24}3×2×24=96 CP of B = 4x=96X= 24CP of A = 25x =25×24=600=25\times{24}=600=25×24=6003A+4B=3×600+4×96=21843A +4B=3\times{600}+4\times{96}=21843A+4B=3×600+4×96=2184 Open explanation in App