Question:
Let x be the least number of 4 digits that when divided by 2, 3, 4, 5, 6 and 7 leaves a remainder of 1 in each case. If x lies between 2000 and 2500, then what is the sum of the digits of x?
A15
B4
C9
D10
Answer:
B. 4
Explanation:
LCM of 2, 3, 4, 5, 6 and 7 is 420. Number should be between 2000 and 2500 so, the number is = 420 × 5 = 2100 Remainder will be 1 in each case so the number is = 2100 + 1 = 2101 Sum of digit of the number 2101 is = 2 + 1 + 0 + 1 = 4