Question: A1B-1C2D-2Answer: A. 1Explanation:312−213−13(512×511)−213=72−73−13(112×511)−53\frac{3\frac{1}{2}-2\frac{1}{3}-\frac{1}{3}}{(5\frac{1}{2}\times \frac{5}{11})-2 \frac{1}{3}} = \frac{\frac{7}{2}-\frac{7}{3}-\frac{1}{3}}{(\frac{11}{2}\times \frac{5}{11})-\frac{5}{3}}(521×115)−231321−231−31=(211×115)−3527−37−31=21−14−2652−53=\frac{\frac{21-14-2}{6}}{\frac{5}{2}-\frac{5}{3}}=25−35621−14−2=5615−106=\frac{\frac{5}{6}}{\frac{15-10}{6}}=615−1065=5656= \frac{\frac{5}{6}}{\frac{5}{6}}=6565=1=1=1
