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What will be the remainder if 2892^{89} is divided by 9?

A2

B3

C4

D5

Answer:

D. 5

Read Explanation:

(289/9)(2^{89}/9)

(23)29×229⇒ \frac{(2^3)^29 × 2^2}{9}

(8)29×49⇒ \frac{(8)^29 \times{4}}{9}

(1)29×49⇒\frac{(-1)^29 × 4}{9}

(1×4)9 ⇒ \frac{(-1\times{4})}{9}

49⇒\frac{ - 4}{9}

⇒ Remainder = - 4 + 9 = 5


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