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3,2,14,8,7,9 എന്നിവയുടെ പരിധിയുടെ ഗുണാങ്കം എത്ര ?

A3/4

B1/2

C2/5

D1/3

Answer:

A. 3/4

Read Explanation:

പരിധിയുടെ ഗുണാങ്കം= H-L/ H+L H = 14 L= 2 പരിധിയുടെ ഗുണാങ്കം= 12 /16


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