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5 men and 6 women can do a piece of work in 6 days while 3 men and 5 women can do the same work in 9 days. In how many days can 3 men and 2 women do the same work?

A$$11\frac{5}{11}$ days$

B$$13\frac{3}{11}$ days$

C$$10\frac{9}{11}$ days$

D$$12\frac{1}{11}$ days$

Answer:

$$11\frac{5}{11}$ days$

Read Explanation:

5M+6W=65M+6W=6 days

3M+5W=93M+5W=9 days

total work is same

(5M+6W)6=(3M+5W)9(5M+6W)6=(3M+5W)9

(5M+6W)2=(3M+5W)3(5M+6W)2=(3M+5W)3

10M+12W=9M+15W10M+12W=9M+15W

M=3WM=3W

MW=31\frac{M}{W}=\frac31

work=(5×3+6×1)6=126=(5\times 3+6\times 1)6=126

the days is

3M+2W=3×3+2×1=9+2=113M+2W=3\times 3+2\times 1=9+2=11

12611=11511\frac{126}{11}=11\frac{5}{11} days


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