The average of 9 numbers is 'x' and the average of three of these is 'y'. If the average of the remaining numbers is 'z', then
A3x +2z=y
B3x - y = 2z
C3x +2y +z=0
DX = 2z+3y.
Answer:
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A3x +2z=y
B3x - y = 2z
C3x +2y +z=0
DX = 2z+3y.
Answer:
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