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910-നെ മൂന്ന് ഭാഗങ്ങളായി വിഭാജിച്ചതിൽ ആദ്യ ഭാഗത്തിന്റെ മൂന്നിലൊന്ന്, രണ്ടാം ഭാഗത്തിന്റെ അഞ്ചിലൊന്ന്, മൂന്നാം ഭാഗത്തിന്റെ ആറിലൊന്ന് എന്നിവ തുല്യമായാൽ രണ്ടാം ഭാഗം എത്ര?

A195

B325

C210

D390

Answer:

B. 325

Read Explanation:

910 നേ വിഭജിച്ചതിൽ 3 ഭാഗങ്ങൾ യഥാക്രമം A, B, C എന്നിങ്ങനെ ആയാൽ (1/3) × A = (1/5) × B = (1/6) × C = x A = 3x, B = 5x C = 6x A + B + C = 910 3x + 5x + 6x = 910 14x = 910 x = 65 രണ്ടാം ഭാഗം = 5x = 5 × 65 = 325


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