Question:
5th പദം 16ഉം 13th പദം 24ഉം ആയ ഒരു സമാന്തര ശ്രേണി കണ്ടെത്തുക.
A10, 12, 14, 16, 18, ......
B13, 15, 17, 19, 21, ......
C12, 13, 15, 17, 19, ......
D12, 13, 14, 15, 16, ......
Answer:
D. 12, 13, 14, 15, 16, ......
Explanation:
5th പദം = 16 16 = a + (5 - 1)d 16 = a + 4d .................(1) 13th പദം =24 24 = a + (13 - 1)d 24 = a + 12d ............(2) (2) - (1) 8 = 8d d = 1 16 = a + (5 -1)1 16= a + 4 a = 12 AP = 12, 13, 14, 15, 16, ......