Question:
If the Seven times of seventh term of an arithmetic progression is Eleven times of its 11th term, then the 18th term of the arithmetic progression will be _____
A1
B0
C2
D-1
Answer:
B. 0
Explanation:
First term is a and common difference is d
n-th term = a + (n-1)d
Seventh term = a + 6d
Eleventh term = a + 10d
Seven times the seventh term is equal to eleven times the eleventh term
7(a + 6d) = 11(a + 10d)
7a + 42d = 11a + 110d
4a = -68d
a = -17d
18th term = a + 17d
= -17d + 17d
= 0