In a circle of radius 5 m, AB and CD are two equal and parallel chords of length 8 m each. What is the distance between the chords?A5 mB6 mC3 mD8 mAnswer: B. 6 m Read Explanation: By Pythagoras theorem, 5² - 4² = 3² The distance between the radius and chord is 3 m The distance between two chords = 2 × 3 = 6 m Read more in App