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In a triangle ABC, angle bisector of ∠B and ∠A intersect at O. ∠C is 82°. What is the measure of ∠BOA?

A121°

B131°

C151°

D90°

Answer:

B. 131°

Read Explanation:

Solution:

Given:

The measure of ∠C = 82° 

Concept used:

The sum of all the angles of the triangle is 180° 

Calculation:

∠A + ∠B + ∠C = 180° 

Dividing by 2

∠A/2 + ∠B/2 + ∠C/2 = 180°/2

⇒ ∠A/2 + ∠B/2 = 90° - 82°/2

⇒ ∠A/2 + ∠B/2 = 49° 

In ΔAOB 

∠A/2 + ∠B/2 + ∠BOA = 180° 

⇒ ∠BOA = 180° - 49° 

⇒ ∠BOA = 131° 

Shortcut Trick

Concept:

The (interior) bisector of an angle, also called the internal angle bisector, is the line or line segment that divides the angle into two equal parts.

Calculation:


image.png

Measure of ∠BOA = (90 + ∠C/2) = (90° + 41°) = 131° 


Related Questions:

In the given figure, If PQ II BC, ∠QPC = 40° and ∠ABC = 57° then find ∠BAC

image.png

O is a point inside the triangle <OBC= <OCA and <OCB= <OBA. <A= 50°. What is the measure of <BOC?

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