In the given figure, PAQ is the tangent. BC is the diameter of the circle. If ∠BAQ = 60°, find angle ABC.

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A25

B30

C45

D60

Answer:

Therefore, in the given figure- ∠BAQ = ∠ACB = 60° (By alternate segment theorem) Since BC is diameter, ∠BAC = 90° ∠ABC = 180°−(90°+60°) = 30°

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