[(5/6)5×(4/3)−4]÷[(5/6)6×(3/4)4]=?[{(5/6)^5\times(4/3)^{-4}}]\div[{(5/6)^6\times(3/4)^4}]=?[(5/6)5×(4/3)−4]÷[(5/6)6×(3/4)4]=? A5/6B6/5C3/4D4/3Answer: B. 6/5 Read Explanation: [(5/6)5×(4/3)−4]÷[(5/6)6×(3/4)4][{(5/6)^5 \times (4/3)^{-4}}]\div[{(5/6)^6 \times(3/4)^4}][(5/6)5×(4/3)−4]÷[(5/6)6×(3/4)4] =(5/6)5×(4/3)−4×(5/6)−6×(3/4)−4= (5/6)^5 \times (4/3)^{-4}\times {(5/6)^{-6}\times (3/4)^{-4} }=(5/6)5×(4/3)−4×(5/6)−6×(3/4)−4 =(5/6)5+(−6)×(4/3)−4×(3/4)−4=(5/6)^{5+(-6)}\times(4/3)^{-4}\times(3/4)^{-4}=(5/6)5+(−6)×(4/3)−4×(3/4)−4 =(5/6)−1=(5/6)^{-1}=(5/6)−1 =6/5=6/5=6/5 Read more in App