Question:
Ramu had to select a list of numbers between 1 and 1000 (including both), which are divisible by both 2 and 7. How many such numbers are there?
A142
B71
C97
D642
Answer:
B. 71
Explanation:
an = a + ( n - 1) × d a = 14 , last term = 994 d = 2nd term - 1st term = 28 - 14 = 14 994 = 14 + ( n - 1) × 14 980 = 14n - 14 994 = 14n n = 71