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A cow is tied on the corner of a rectangular field of size 30 m ×20 m by a 28m long rope. The area of the region, that she can graze, is(useπ=227) (use \pi =\frac{ 22}{ 7} ) :

A400 sqcm

B576 sqcm

C616 sqcm

D700 sqcm

Answer:

C. 616 sqcm

Read Explanation:

Given Radius, r= 28 =length of rope

Required area =π4r2=\frac{\pi}{4}r^2

=22×2827×4=616m2=\frac{22\times{28^2}}{7\times{4}}= 616m^2


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