Question

$$Find the unit digit of $(432)^{412} × (499)^{431}$

• A. 2
• B. 4
• C. 6
• D. 8

Answer 1

Answer:

B. 4

9^even no. = unit digit 1 9^odd no. = unit digit 9 2^1 = 2 2^2 =4 2^3 = 8 2^4 = 6 2^5 = 2, In case of powers of 2 ; 2,4,8, 6 , the pattern repeats ⇒ 2^412 × 9^431 = 2^(4 × 103) × 9^(431) ⇒ 6 × 9 ⇒ 54