App Logo

No.1 PSC Learning App

1M+ Downloads

Find the value of tan60tan151+tan60tan15\dfrac{\tan 60^\circ - \tan 15^\circ}{1 + \tan 60^\circ \tan 15^\circ}

A1

B12\frac{1}{\sqrt{2}}

C12\frac{1}{2}

D32\frac{\sqrt{3}}{2}

Answer:

A. 1

Read Explanation:

Solution:

Given:


tan60tan151+tan60tan15\dfrac{\tan 60^\circ - \tan 15^\circ}{1 + \tan 60^\circ \tan 15^\circ}

Formula:

tan (A - B) = (tan A - tan B)/(1 + tan A tan B)

tan 45° = 1

Calculation:

(tan 60° - tan 15°)/(1 + tan 60° tan 15°)

⇒ tan (60° - 15°)

⇒ tan 45°

⇒ 1


Related Questions:

Cos1o.cos2o.cos3o.......................cos100o is equal to

figure shows a triangle and its circumcircle what is the radius of the circle

1000115094.jpg

AC=5 cm, angle ABC =60°

In a ΔABC right triangle at B. If SinC=6061SinC=\frac{60}{61} and CosA=6061CosA=\frac{60}{61}, then find the value of the expression tanA+cot(A+C)CotC+SecASinC\frac{tanA+cot(A+C)}{CotC+SecASinC}

Find the value of

Sin0o×sin1o×sin2o×sin30...............Sin890isSin0^o\times{sin1^o}\times{sin2^o}\times{sin3^0}...............Sin89^0 is

image.png