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10x×45x=28\frac{10^x \times 4}{5^x}=2^8 ആയാൽ x-ന്ടെ വില എത്ര?

A4

B2

C3

D6

Answer:

D. 6

Read Explanation:

10x×45x=28\frac{10^x \times 4}{5^x}=2^8

(2×5)x×225x=28\frac{(2 \times 5)^x \times 2^2}{5^x}=2^8

2x×5x×225x=28\frac{2^x \times 5^x \times 2^2}{5^x}=2^8

2x+2=282^{x+2}=2^8

x+2=8x+2=8

x=6x=6


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