What is the degree of p(x)+q(x):p(x)=4x4+3x2+6x+9p(x)=4x^4+3x^2+6x+9p(x)=4x4+3x2+6x+9,q(x)=5x4+6x3+8q(x)=5x^4+6x^3+8q(x)=5x4+6x3+8 A8B3C4D6Answer: C. 4 Read Explanation: p(x)=4x4+3x2+6x+9p(x)=4x^4+3x^2+6x+9p(x)=4x4+3x2+6x+9,q(x)=5x4+6x3+8q(x)=5x^4+6x^3+8q(x)=5x4+6x3+8p(x)+q(x)=9x4+6x3+3x2+6x+17p(x)+q(x)=9x^4+6x^3+3x^2+6x+17p(x)+q(x)=9x4+6x3+3x2+6x+17degree of p(x)+q(x) =4 Read more in App