Solution:
Given:
The area of a square and a rectangle is equal
The length of the rectangle is 6 cm more than the side of the square
The breadth of the rectangle is 4 cm less than the side of the square
Formula Used:
1. Area of Square = a2
2. Area of Rectangle = l × b
3. Perimeter of Rectangle = 2(l + b)
Where, a = side of square, l & b are length & breadth of rectangle respectively
Calculation:
Let the side of square be a
⇒ Length of rectangle = a + 6
⇒ Breadth of rectangle = a - 4
According to the question,
a2 = (a + 6)(a - 4)
⇒ a2 = a2 - 4a + 6a - 24
⇒ 2a = 24
⇒ a = 12
Perimeter of Rectangle = 2[(12 + 6) + (12 - 4)]
⇒ Perimeter of Rectangle = 2(18 + 8) = 52 cm
∴ The perimeter of rectangle is 52 cm.