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The LCM and HCF of two numbers are 20 and 120 respectively. if one number is 50% more than the other number. What is the smaller number of the two

A20

B40

C60

D80

Answer:

B. 40

Read Explanation:

let the numbers be N1, N2 LCM = 120, HCF = 20 If N1 = 100, N2 - 150 N1/N2 = 100/150 = 2/3 = a/b N1 = HCF × a = 20 × 2 = 40 N2 = HCF × b = 20 × 3 = 60


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