What is the largest number if the average of 7 consecutive natural numbers is 43?
A46
B45
C47
D49
Answer:
A. 46
Read Explanation:
If the consecutive 7 natural numbers are
a, a+1, a+2, a+3, a+4, a+5, a+6
Average = (7a+21)/7=43
7a+21=43x7
7a+21=301
7a=280
a=280/7
=40
Largest number= a+6
= 40+6
= 46
