Question:
What is the largest number if the average of 7 consecutive natural numbers is 43?
A46
B45
C47
D49
Answer:
A. 46
Explanation:
If the consecutive 7 natural numbers are a, a+1, a+2, a+3, a+4, a+5, a+6 Average = (7a+21)/7=43 7a+21=43x7 7a+21=301 7a=280 a=280/7 =40 Largest number= a+6 = 40+6 = 46