Question:
A purse contains coins of 2 Rupees, 1 Rupee, 50 paise and 25 paise in the ratio 1:2:4:8. If the total amount is Rs.600, then the number of 25 paise coins exceeding those of 50 paise coins is :
A300
B200
C100
D400
Answer:
A. 300
Explanation:
the number of 2 Rupees, 1 Rupee, 50 paise, and 25 paise coins is in the ratio 1:2:4:8. - Let the number of 2 Rupee coins be x - The number of 1 Rupee coins will be 2x - The number of 50 paise coins will be 4x - The number of 25 paise coins will be 8x Now, let's calculate the total amount using these quantities: - The total value of 2 Rupee coins = 2 X x - The total value of 1 Rupee coins = 1 X 2x = 2x - The total value of 50 paise coins = 0.50 X 4x = 2x - The total value of 25 paise coins = 0.25 X 8x = 2x The total amount of money is given as Rs.600, so: 2x + 2x + 2x + 2x = 600 8x = 600 x = 600/8 = 75 Now, using x = 75, let's calculate the number of coins: - The number of 2 Rupee coins = x = 75 - The number of 1 Rupee coins = 2x = 150 - The number of 50 paise coins = 4x = 300 - The number of 25 paise coins = 8x = 600 Excess number of 25 paise coins = 600 - 300 = 300