Question:
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
A39, 30
B41, 32
C42, 33
D43, 34
Answer:
C. 42, 33
Explanation:
Let their marks be (x + 9) and x. x + 9 = 56/100(x + 9 + x) 25(x + 9) = 14(2x + 9) 3x = 99 x = 33 So, their marks are 42 and 33.