Practice Questions

In the figure &lt;BOX = t⁰ , Coordinates of B are (½,½). What is sin t?

In △ APC ∠ APC = 180° - 60° = 120°So ∠ACP = 180° - (120 + 30 ) = 30°Triangle APC is an isosceles triangle So AP = PC = 10 cmIn △ PBC ∠ PBC = 90°∠ BPC = 60°∠ PCB = 30°Ratio 30° : 60° : 90° = 1 : √3 : 2PC = 2 =  10cm PB = 1 = 5BC = 5√3So,AB = 15 cmBC = 5√3Area of ABCD = length × breadth = 15 × 5√3= 75√3 cm²

In the figure &lt;CAB=30°, &lt;CPB=60°. AP 10 centimeters. Area of the rectangle ABCD is.............................. square centimeters.

tan 45 = 1 

sec 60 = 2

tan 45 + sec 60= 1 + 2 

= 3

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If tan 45 + sec 60 = x, find the value of x.

If tan x = cot(45° + 2x), then what is the value of x?