Which term of this arithmetic series is zero: 150, 140, 130 ...?

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Question:

Which term of this arithmetic series is zero: 150, 140, 130 ...?

A16

B17

C15

D18

Answer:

A. 16

Explanation:

The first term, a = 150, common difference is d = -10, n-th term is 0. n-th term tn = a + (n-1)d So 0 = 150 + (n - 1) x-10 - 150 = (n-1)x-10 n - 1 = 150/10 = 15 n=15+ 1 = 16

Related Questions:

If -6, x, 10 are in A.P, then 'x' is :

ഒരു A.P യുടെ തുടർച്ചയായ മൂന്ന് പദങ്ങളുടെ ആകെത്തുക 48 ഉം ഒന്നാമത്തെയും മൂന്നാമത്തെയും പദങ്ങളുടെ ഗുണനഫലം 252 ഉം ആയാൽ ശ്രേണിയുടെ പൊതു വ്യത്യാസം എന്ത് ?

Tailors Abraham and Joju need to stitch 400 bags. On the first day, Abraham stitches 13 bags, and Joju stitches 18 bags. Each following day, both of them stitch one more bag than they did the previous day. How many days will it take for them to complete their goal?

Challenger

Which term of this arithmetic series is zero: 150, 140, 130 ...?

A. 16

Explanation:

If -6, x, 10 are in A.P, then 'x' is :

Tailors Abraham and Joju need to stitch 400 bags. On the first day, Abraham stitches 13 bags, and Joju stitches 18 bags. Each following day, both of them stitch one more bag than they did the previous day. How many days will it take for them to complete their goal?

3,7,11,15 ..... എന്ന സമാന്തര ശ്രേണിയിലെ 25 പദം എത്ര ?

ഒരു സമാന്തര ശ്രേണിയുടെ 10 ആമത്തെയും 20 ആമത്തേയും പദങ്ങളുടെ തുക 60 ആയാൽ, 14 ആമത്തെയും 16 ആമത്തേയും പദങ്ങളുടെ തുക എത്ര ?