Question:
Find the value of 1²+2²+3²+.....+10²
A425
B325
C385
D400
Answer:
C. 385
Explanation:
Sum of squares of first 'n natural numbers =[n(n+1) (2n+1) /6] = 10 (10+1) (2 x10+1) / 6 = (10 x 11 x 21) / 6 = 385
Related Questions:
Question:
A425
B325
C385
D400
Answer:
Sum of squares of first 'n natural numbers =[n(n+1) (2n+1) /6] = 10 (10+1) (2 x10+1) / 6 = (10 x 11 x 21) / 6 = 385
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