Find the value of 1²+2²+3²+.....+10²A425B325C385D400Answer: C. 385Read Explanation:Sum of squares of first 'n natural numbers =[n(n+1) (2n+1) /6] = 10 (10+1) (2 x10+1) / 6 = (10 x 11 x 21) / 6 = 385Open explanation in App