Two masses M1 = M and M2 = 4M possess an equal amount of kinetic energy, then the ratio of their momentum p1 : p2 is?A1 : 4B4 : 1C2 : 1D1 : 2Answer: D. 1 : 2Read Explanation:Kinetic Energy = 1/2 mv2Linear momentum, P = mvRelation between Linear momentum and KE isKinetic Energy = 1/2 mv2= P2/2mGiven in the question, KE is equal for both objects, that is,P12/2M1 = P22/2M2Given in the question,M1 = MM2 = 4MThen the ratio of their momentum P1 : P2 is,P12/2M1 = P22/2M2P1 2 / P22= 2M1 / 2M2P1 / P2= √2M1 / √2M2P1 / P2= √2M/ √2 x 4MP1 / P2= √2/√8 = 1/√4 = 1/2P1 : P2 = 1:2 Open explanation in App