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72×9327×343=? \frac {7^2 \times 9^3}{27 \times 343} = ?

A$\frac {27}{7}$

B$\frac {27}{21}$

C$\frac {7}{27}$

D$\frac {21}{27}$

Answer:

$\frac {27}{7}$

Read Explanation:

72×9327×343 \frac {7^2 \times 9^3}{27 \times 343}

=72×9333×73= \frac {7^2 \times 9^3}{3^3 \times 7^3}

=72×(32)333×73= \frac {7^2 \times (3^{2)^3}}{3^3 \times 7^3}

=72×3633×73= \frac {7^2 \times 3^6}{3^3 \times 7^3}

=337= \frac {3^3}{7}

=27/7= 27/7


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