Question:72×9327×343=? \frac {7^2 \times 9^3}{27 \times 343} = ?27×34372×93=? A$\frac {27}{7}$B$\frac {27}{21}$C$\frac {7}{27}$D$\frac {21}{27}$Answer: $\frac {27}{7}$Explanation:72×9327×343 \frac {7^2 \times 9^3}{27 \times 343} 27×34372×93 =72×9333×73= \frac {7^2 \times 9^3}{3^3 \times 7^3} =33×7372×93 =72×(32)333×73= \frac {7^2 \times (3^{2)^3}}{3^3 \times 7^3} =33×7372×(32)3 =72×3633×73= \frac {7^2 \times 3^6}{3^3 \times 7^3}=33×7372×36 =337= \frac {3^3}{7}=733 =27/7= 27/7=27/7
