$ \frac {7^2 \times 9^3}{27 \times 343} =? $

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$\frac {7^2 \times 9^3}{27 \times 343} = ?$

A$\frac {27}{7}$

B$\frac {27}{21}$

C$\frac {7}{27}$

D$\frac {21}{27}$

Answer:

$\frac {27}{7}$

$\frac {7^2 \times 9^3}{27 \times 343}$

$= \frac {7^2 \times 9^3}{3^3 \times 7^3}$

$= \frac {7^2 \times (3^{2)^3}}{3^3 \times 7^3}$

$= \frac {7^2 \times 3^6}{3^3 \times 7^3}$

$= \frac {3^3}{7}$

$= 27/7$

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