A0
B1
C2
D3
Answer:
Related Questions:
48−12×3+810−18÷3\frac{48-12\times3+8}{10-18\div3}10−18÷348−12×3+8
The value of −48÷[4×(6−5+1)]÷24 -48 \div [4 \times (6 - 5 + 1)] \div 24−48÷[4×(6−5+1)]÷24:
Find the value of
[(42÷7)×(423+194×(8−4))][(42\div7)\times(\frac{42}{3}+\frac{19}{4}\times(8-4))][(42÷7)×(342+419×(8−4))]
