(1 + 1/2)(1 + 1/3)(1 + 1/4) x .....(1+ 1/98)(1 + 1/99)

Challenger

☰

Question:

B50

D100

Answer:

$(1+\frac12)\times(1+\frac13)\times......\times(1+\frac1{99})$

$=\frac{(1+2)}{2}\times\frac{(1+3)} 2\times.......\times\frac{(1+99)}{99}$

$=\frac32\times\frac43\times\frac54\times......\times\frac{100}{99}$

$=\frac{100}2$

$=50$

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