Question:
The age of mother 10 years ago was thrice the age of her daughter. 10 years hence mother's age will be twice that of her daughter. The ratio of their present ages is
A5:2
B7:3
C9:2
D13:2
Answer:
B. 7:3
Explanation:
n1= 10 x=3 n2=10 y=2 Present age of daughter =(n1(x-1)+n2(y-1))/(x-y) =(10(3-1)+10(2-1))/(3-2) =(20+10)/1=30 10 years ago daughter's age = 30 - 10 = 20 10 years ago mother's age = 20x3 = 60 Present age of mother = 60+10 = 70 Ratio of their ages = 70:30 = 7:3