Question

(-1)^5 + (-1)^10 – (-1)^20 / 1^0 ?

• A. 1
• B. 0
• C. -1
• D. 2

Answer 1

Answer:

C. -1

Read Explanation:

$(-1)^5 + (-1)^{10}-(-1)^{20} / 1^0$

$=-1+1-1/1$

$=-1$

$(-1)^{n} = 1$ ; n = ഇരട്ട സംഖ്യ

$(-1)^{n}=-1$ ; n = ഒറ്റ സംഖ്യ

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