$rac{3}{2} + rac{2}{3}\ ext{ ÷ } rac{3}{2}

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$\frac{3}{2} + \frac{2}{3}\div \frac{3}{2} - \frac{1}{2} =$

A11/6

B13/9

C3/2

Answer:

$\frac{3}{2} + \frac{2}{3}\div\frac{3}{2} - \frac{1}{2} = \frac{3}{2} + \frac{2}{3}\times \frac{2}{3} - \frac{1}{2}$

= $\frac{3}{2} + \frac{4}{9} -\frac{1}{2}$

$= 1 + \frac{4}{9}$

= $\frac{13}{9}$

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