ABCD is a cyclic quadrilateral such that AB is a diameter of the circle circumscribing it and angle ADC = 140°. Then angle BAC is equal to∶
A38
B40
C50
D60
Answer:
A38
B40
C50
D60
Answer:
Related Questions:
In the given figure, PAQ is the tangent. BC is the diameter of the circle. If ∠BAQ = 60°, find angle ABC.