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A1:4

B2:1

C1:2

D1:1

Answer:

D. 1:1

Read Explanation:

sin2A+cos2A=1sin^2A+cos^2A=1

sin2A=cos2(90−A)sin^2A=cos^2(90-A)

cos2A=sin2(90−A)cos^2A=sin^2(90-A)

sin⁡222+sin268cos233+cos257\frac{\sin^2{22}+sin^2{68}}{cos^2{33}+cos^2{57}}

sin⁡222+cos222cos233+sin233\frac{\sin^2{22}+cos^2{22}}{cos^2{33}+sin^2{33}}

1:11:1

Related Questions:

The value of cosec230∘sin⁡245∘+sec⁡260∘tan60∘cosec245∘−sec⁡260∘tan45∘\frac{{\rm cose{c^2}30^\circ {{\rm \sin }^2}45^\circ + {{\rm \sec }^2}60^\circ }}{{\rm tan60^\circ \rm cose{c^2}45^\circ - {{\rm \sec }^2}60^\circ \rm tan45^\circ }}  is:

The value of tan(–405°) is :

A. 1

B. –1

C. ∞

D. 0

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If sinx=1237sinx=\frac{12}{37} , then what is the value of tan x?