Question

(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0 ആയാൽ (1/x - 1/y - 1/z) എത്രയാണ്?

• A. 1
• B. 6/5
• C. 5/6
• D. 0

Answer 1

Answer:

C. 5/6

(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0 3 - 6/x - 4 + 6/y + 6 + 6/z = 0 6/x - 6/y - 6/z = 5 1/x - 1/y - 1/z = 5/6