If (3x - 6)/x - (4y - 6)/y + (6z + 6)/z = 0, then what is (1/x - 1/y

Challenger App

★

1M+ Downloads

(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0 ആയാൽ (1/x - 1/y - 1/z) എത്രയാണ്?

B6/5

C5/6

Answer:

(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0 3 - 6/x - 4 + 6/y + 6 + 6/z = 0 6/x - 6/y - 6/z = 5 1/x - 1/y - 1/z = 5/6

Related Questions:

x + 1 = 23 എങ്കിൽ 3x +1 എത്ര ?

If $\theta$ is an acute angle, find the denominator A, when $(cosec\theta-cot\theta)^2=\frac{1-cot\theta}{A}$

If a + b + c = 6, $a^2 + b^2 + c^2 = 30$ and $a^3 + b^3 + c^3 = 165,$ then the value of 4abc is:

If $x ^ 2 + 1 / x ^ 2 =23$ find the value of $x + 1 / x$