Question

If $(3x - 6)/x - (4y - 6)/y + (6z + 6)/z = 0$, then what is $(1/x - 1/y - 1/z)?$

• A. 1
• B. 6/5
• C. 5/6
• D. 0

Answer 1

Answer:

C. 5/6

$(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0$

$3 - 6/x - 4 + 6/y + 6 + 6/z = 0$

$-6/x + 6/y + 6/z = -6 + 4 - 3$

$-(6/x - 6/y - 6/z) = -5$

$6/x - 6/y - 6/z = 5$

$1/x - 1/y - 1/z = 5/6$