If X # Y = XY + X - Y, what is the value of (6#5) × (3#2)?

Challenger App

No.1 PSC Learning App

★

★

★

★

★

1M+ Downloads

X # Y = XY + x - Y ആണ് എങ്കിൽ (6#5)× (3#2) എത്ര?

A287

B127

C217

D147

Answer:

C. 217

Read Explanation:

6#5 = 30 + 6 - 5 = 31 3 # 2 = 6 + 3 - 2 = 7 (6#5)× (3#2) = 31 × 7 = 217

Read more in App

Related Questions:

The factors of x³-4x²+x+6 is:

If x + y = 15 and xy = 14, then the value of x – y is :

Solve, $(x-1)^2 = [4\sqrt{(x-4)}]^2$

If $4a+\frac{1}{5a}=4$ , then the value of $25a^2+\frac{1}{16a^2}$ is:

If p : q = r : s , s = 4p² and 2qr = 64, then find the value of 2p + 3s