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In ΔABC, if ∠A = 40° and ∠B = 70°, find the measure of exterior angle at A.

A140°

B110°

C70°

D30°

Answer:

A. 140°

Read Explanation:

The exterior angle is equal to the sum of the two opposite interior angles. Thus ,exterior angle at A = 70° + 70° = 140°.


Related Questions:

ABCD is a Rhombus. AC=8 centimeters, BD =6 centimeters what is the perimeter of ABCD?

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