Question

Amita travels from her house at $3\frac{1}{2}$ km/h and reaches her school 6 minutes late. The next day she travels at $4\frac{1}{2}$ km/h and reaches her school 10 minutes early. What is the distance between her house and the school?

• A. 5.6 km
• B. 5.4 km
• C. 4.8 km
• D. 4.2 km

Answer 1

Answer:

D. 4.2 km

Solution: Given: Speed 1 = 3.5 km/hr reaches 6 min late Speed 2 = 4.5 km/h reaches 10 min early. Formula used: Distance = [(Speed 1 × Speed 2)/(Difference of Speeds)] × time difference Calculation: Distance = [(Speed 1 × Speed 2)/(Difference of Speeds)] × time difference ⇒ Distance = [(3.5 × 4.5)/1] × 16/60 ⇒ 4.2 km ∴ The distance between her house and the school is 4.2 km. Mistakes Point: Convert all given data in same units i.e all-time in an hour or sec and distance in Km or meter according to requirements.