(255)x=(35)x+1(25\sqrt{5})^{x}=(^3\sqrt5)^{x+1}(255)x=(35)x+1, x തുല്യമായത് ഏതാണ്? A1/5B2/13C2/15D5/3Answer: B. 2/13 Read Explanation: (255)x=(35)x+1(25\sqrt{5})^{x}=(^3\sqrt5)^{x+1}(255)x=(35)x+1(52×51/2)x=(51/3)x+1(5^2\times5^{1/2})^x=(5^{1/3})^{x+1}(52×51/2)x=(51/3)x+155x/2=5(x+1)/35^{5x/2}=5^{(x+1)/3}55x/2=5(x+1)/35x/2=(x+1)/35x/2=(x+1)/35x/2=(x+1)/315x=2x+215x=2x+215x=2x+213x=213x=213x=2x=2/13x=2/13x=2/13 Read more in App