What is the number of rounds that a wheel of diameter $\frac{5}{11}m will make in traversing 7 km? A3300B3500C4400D4900Answer: D. 4900 Read Explanation: Solution:Distance=Circumference×No.ofRevolutionDistance=Circumference\times{No.of Revolution}Distance=Circumference×No.ofRevolutionDistance = 7 kmDiameter=511mDiameter =\frac{5}{11}mDiameter=115mRadius=5112Radius=\frac{\frac{5}{11}}{2}Radius=2115Radius,r=522Radius,r=\frac{5}{22}Radius,r=225Circumference of Wheel = 2πr2\pi{r}2πr=2×227×522= 2\times{\frac{22}{7}}\times{\frac{5}{22}}=2×722×225=107=\frac{10}{7}=7107km=107×No.ofRevolution7km=\frac{10}{7}\times{No.of Revolution}7km=710×No.ofRevolutionNo.ofRevolution=710×1000No.of Revolution=\frac{7}{10}\times{1000}No.ofRevolution=107×1000=4900=4900=4900 Read more in App